I assume that the poster meant: y=e^x tan sqrt {5x} By rewriting the square-root as the 1/2-power, y=e^xtan (5x)^ {1/2} Let us now find the derivative.

#x+sqrt (x^2+4)=color (red) (2y)color (white) ("xxxxxx")#...or at least that's what I got

vertex is (2,5) (0,9) is the y intercept no x intercepts Complete the square y= (x-2)^2-4+9 y= (x-2)^2+5 so the vertex is (2,5) If y=x^2-4x+9 when x=0, y=9 If we take the equation after we …

x=1 or x=9 (see below for method of completing the square). A general squared binomial has the relation: color (white) ("XXX") (a+b)^2=a^2+2ab+b^2 If x^2+8x are the first two terms of an …

Divide both sides by 2 #x^2= (12sqrt (2))^2/2# Square root both sides #x= (12sqrt (2))/sqrt (2) = 12xxsqrt2/sqrt2# But #sqrt2/sqrt2=1# #x=12# cm # larr" 1 side of the square"# …

1 Answer Andrea S. Apr 18, 2018 By definition of derivative, #F# is differentiable in #x_0# if the limit: #lim_ (x->x_0) (F (x)-F (x_0))/ (x-x_0)#

Derivative of f (g (x)) is 32sec^2 16x. As f (x)=tan8x, (df)/ (dx)=sec^2 8x*8=16sec^2 8x and as g (x)=2x (dg)/ (dx)=2 and f (g (x))=tan8 (2x)=tan16x and according to ...

How do you simplify a radical expression if a variable with a negative exponent is on the top (as the numerator)? How do I rationalize Cubic root? How do you simplify #sqrt (x^3y^4)#? What …

The most common things to look at when considering the domain of a function are: Division by 0 Square root of a negative number Natural logarithm of non-positive number Test for the …

Sep 20, 2017 · Explanation: Recall that derivative of #x^n# is #nx^ (n-1)# hence derivative of #x^ (-20)# is #-20x^ (-21)=-20/x^21# As #f (x)= (x/100)^ (-20)=1/100^ (-20)xx x^ (-20 ...